Showing posts with label coded. Show all posts
Showing posts with label coded. Show all posts

Monday, March 12, 2012

Group chart by month

I have a really basic chart that pulls data from a SQL table. I have
the dataset asking for a machine number. The date range is hard coded
in the query for now.
This is my table's basic data...
Machine | Performance | DateTime
____________________________
1125 | 60 | 11/16/06
1125 | 45 | 12/01/06
1125 | 35 | 12/15/06
The results give me all the machines details from sept06 through
feb07. The series is the machine, Y axis is the performace and the X
Axis is the date formated by MM/YY
Right now the chart shows me 3 records. one for 11/06 and two for
12/06. Each record has a bar for the proper performance number.
What I need is 2 records.
11/06 and the bar will represent the avg for all Nov records.
12/06 and the bar will represent the avg for all Dec records.
I'm not sure if I have to change the dataset query or adjust the
groupings or whatever in the table. I'm lost right now."Bruce Lawrence" <BL32375@.gmail.com> wrote in message
news:1170436640.424961.261770@.p10g2000cwp.googlegroups.com...
>I have a really basic chart that pulls data from a SQL
>table. I have
> the dataset asking for a machine number. The date range
> is hard coded
> in the query for now.
> This is my table's basic data...
> Machine | Performance | DateTime
> ____________________________
> 1125 | 60 | 11/16/06
> 1125 | 45 | 12/01/06
> 1125 | 35 | 12/15/06
> The results give me all the machines details from sept06
> through
> feb07. The series is the machine, Y axis is the
> performace and the X
> Axis is the date formated by MM/YY
> Right now the chart shows me 3 records. one for 11/06 and
> two for
> 12/06. Each record has a bar for the proper performance
> number.
> What I need is 2 records.
> 11/06 and the bar will represent the avg for all Nov
> records.
> 12/06 and the bar will represent the avg for all Dec
> records.
> I'm not sure if I have to change the dataset query or
> adjust the
> groupings or whatever in the table. I'm lost right now.
>
I suggest you change the query. You don't mention a primary
key. You need one. You can then filter the data in your SQL
query. May I suggest you ask this question in one of the SQL
Server newsgroups (such as
microsoft.public.sqlserver.newusers, or
microsoft.public.sqlserver.programming) and give them your
full table structure and the query you are using. Include an
example of the results you want and the incorrect results
you are getting now.
Hope this helps.
Ron.

Sunday, February 26, 2012

GROUP BY column-name problem (need expression)

Please advise on how to get the GROUP BY coded in an acceptable way:

DECLARE @.LO INT
DECLARE @.HI INT
DECLARE @.StartDate varchar(10)
DECLARE @.EndDate varchar(10)

SELECT @.StartDate = '01/01/2005'
SELECT @.EndDate = '06/30/2005'
SELECT @.LO= 250
SELECT @.HI= 333

SELECT
StateCD
, CountyCD
, Zip
, Z.CityName
, Z.StateCode
, Z.CountyName
, 'Criteria' = 'JumboRange:' + Convert(varchar(4),@.LO) + '-' +
Convert(varchar(4),@.HI)
, 'StartingDate' = @.StartDate
, 'ThruDate' = @.EndDate
, JumboAmount = SUM(JumboAmount)
, JumboMortgages = SUM(JumboMortgages)
, JumboFIXMortgages= SUM(JumboFIXMortgages)
, JumboFIXAmount = SUM(JumboFIXAmount)
, JumboARMMortgages = SUM(JumboARMMortgages)
, JumboARMAmount= SUM(JumboARMAmount)
FROM LoanDetails T INNER JOIN dbo.ZipCodesPreferred Z
ON T.StateCD = Z.FIPS_State AND T.CountyCD = Z.FIPS_County AND T.Zip =
Z.ZipCode
GROUP BY
StateCD
, CountyCD
, Zip
, Z.CityName
, Z.StateCode
, Z.CountyName
, 'Criteria' = 'JumboRange:' + Convert(varchar(4),@.LO) + '-' +
Convert(varchar(4),@.HI)
, 'StartingDate' = @.StartDate
, 'ThruDate' = @.EndDateYou don't need the non-column expressions in the GROUP BY list. Column
aliases aren't permitted either. Try:

...
GROUP BY statecd, countycd, zip, Z.cityname, Z.statecode, Z.countyname

--
David Portas
SQL Server MVP
--|||Here is how a SELECT works in SQL ... at least in theory. Real
products will optimize things, but the code has to produce the same
results.

a) Start in the FROM clause and build a working table from all of the
joins, unions, intersections, and whatever other table constructors are
there. The <table expression> AS <correlation name> option allows you
give a name to this working table which you then have to use for the
rest of the containing query.

b) Go to the WHERE clause and remove rows that do not pass criteria;
that is, that do not test to TRUE (i.e. reject UNKNOWN and FALSE). The
WHERE clause is applied to the working set in the FROM clause.

c) Go to the optional GROUP BY clause, make groups and reduce each
group to a single row, replacing the original working table with the
new grouped table. The rows of a grouped table must be group
characteristics: (1) a grouping column (2) a statistic about the group
(i.e. aggregate functions) (3) a function or (4) an expression made up
those three items.

d) Go to the optional HAVING clause and apply it against the grouped
working table; if there was no GROUP BY clause, treat the entire table
as one group.

e) Go to the SELECT clause and construct the expressions in the list.
This means that the scalar subqueries, function calls and expressions
in the SELECT are done after all the other clauses are done. The
"AS" operator can also give names to expressions in the SELECT
list. These new names come into existence all at once, but after the
WHERE clause, GROUP BY clause and HAVING clause has been executed; you
cannot use them in the SELECT list or the WHERE clause for that reason.

If there is a SELECT DISTINCT, then redundant duplicate rows are
removed. For purposes of defining a duplicate row, NULLs are treated
as matching (just like in the GROUP BY).

f) Nested query expressions follow the usual scoping rules you would
expect from a block structured language like C, Pascal, Algol, etc.
Namely, the innermost queries can reference columns and tables in the
queries in which they are contained.

g) The ORDER BY clause is part of a cursor, not a query. The result
set is passed to the cursor, which can only see the names in the SELECT
clause list, and the sorting is done there. The ORDER BY clause cannot
have expression in it, or references to other columns because the
result set has been converted into a sequential file structure and that
is what is being sorted.

As you can see, things happen "all at once" in SQL, not "from left to
right" as they would in a sequential file/procedural language model. In
those languages, these two statements produce different results:
READ (a, b, c) FROM File_X;
READ (c, a, b) FROM File_X;

while these two statements return the same data:

SELECT a, b, c FROM Table_X;
SELECT c, a, b FROM Table_X;

Think about what a confused mess this statement is in the SQL model.

SELECT f(c2) AS c1, f(c1) AS c2 FROM Foobar;

That is why such nonsense is illegal syntax.